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2x^2=5x-35
We move all terms to the left:
2x^2-(5x-35)=0
We get rid of parentheses
2x^2-5x+35=0
a = 2; b = -5; c = +35;
Δ = b2-4ac
Δ = -52-4·2·35
Δ = -255
Delta is less than zero, so there is no solution for the equation
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